3x^2-28=2x^2+33

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Solution for 3x^2-28=2x^2+33 equation:


Simplifying
3x2 + -28 = 2x2 + 33

Reorder the terms:
-28 + 3x2 = 2x2 + 33

Reorder the terms:
-28 + 3x2 = 33 + 2x2

Solving
-28 + 3x2 = 33 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
-28 + 3x2 + -2x2 = 33 + 2x2 + -2x2

Combine like terms: 3x2 + -2x2 = 1x2
-28 + 1x2 = 33 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-28 + 1x2 = 33 + 0
-28 + 1x2 = 33

Add '28' to each side of the equation.
-28 + 28 + 1x2 = 33 + 28

Combine like terms: -28 + 28 = 0
0 + 1x2 = 33 + 28
1x2 = 33 + 28

Combine like terms: 33 + 28 = 61
1x2 = 61

Divide each side by '1'.
x2 = 61

Simplifying
x2 = 61

Take the square root of each side:
x = {-7.810249676, 7.810249676}

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